shafrachetti3321 shafrachetti3321
  • 25-03-2021
  • Mathematics
contestada

A sine curve with a period of 8, an amplitude of 2, a left phase shift of /3, and a vertical translation down 5 units.

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raphealnwobi
raphealnwobi raphealnwobi
  • 26-03-2021

Answer:

[tex]y=2sin[\frac{\pi}{4}(x+3) ]-5[/tex]

Step-by-step explanation:

The standard form for a sinusoidal function is given by:

y = Asin[B(x - C)] + D

Where A is the amplitude of the sine wave, the period is 2π/B, C is the phase shift and D is the vertical displacement / translation

Given:

A = 2, D = -5 (down), C = -3 (left).

8 = 2π/B; B = π/4

Therefore:

[tex]y=2sin[\frac{\pi}{4}(x+3) ]-5[/tex]

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