Find the limit of n*sin(pi/n). ...?

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22-11-2016
Physics

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Find the limit of n*sin(pi/n). ...?

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Аноним Аноним · Answer 1 · 2016-11-25T07:31:43+01:00

The solution to the problem is as follows:

=lim n->∞ sin(PI/n) / (1/n)

0/0 form : Use L'Hopital's Rule

=lim n->∞ (-PI /n^2)cos(PI/n) /(-1/n^2)

= lim n->∞ PI cos(PI/n)

as n->∞ , cos(PI/n) -> cos(0)=1

so the limits is 'PI'

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