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An 886 mL sample of Neon gas is at 752 torr and 299 K. What will be the new volume if, with the pressure and amount of gas held constant the temperature is increased to 371 K?

Respuesta :

sebassandin

Answer:

[tex]V_2=1099.35mL[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible to infer that as both the amount of the gas and the pressure remains the same, we can solve this problem via the Charles' law a directly proportional relationship between the volume and temperature:

[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]

Thus, by solving for the final volume, V2, we obtain:

[tex]V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{886mL*371K}{299K}\\\\V_2=1099.35mL[/tex]

Best regards!

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