arandamariapaula arandamariapaula
  • 26-04-2021
  • Chemistry
contestada

What pressure will be needed to reduce the volume of 77.4 L of helium at 98.0kPa to a volume of 60.0L?

Respuesta :

Stephen46
Stephen46 Stephen46
  • 26-04-2021

Answer:

126 kPa

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

98 kPa = 98,000 Pa

We have

[tex]P_2 = \frac{98000 \times 77.4}{60} = \frac{7585200}{60} \\ = 126420[/tex]

We have the final answer as

126 kPa

Hope this helps you

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