Answer:
[OH⁻] = 0.00524
Explanation:
Given that,
The value of pOH of a solution is 2.28
We need to find the [OH-] in a solution. We know that,
[tex]pOH=-\text{log}[OH^-][/tex]
Put all the values,
[tex]2.28=-\log[OH^-]\\\\=0.00524[/tex]
So, the value of [OH-] in a solution is equal to 0.00524.
