Answer:
[tex]m_{P_2Cl_5 }=239.2125gP_2Cl_5[/tex]
Explanation:
Hello there!
In this case, according to the reaction:
[tex]4P+5Cl_2\rightarrow 2P_2Cl_5[/tex]
Thus, since there is a 4:2 mole ratio of P to P2Cl5 and the molar mass of the later is 239.2125 g/mol, we obtain the following mass as the produced one:
[tex]m_{P_2Cl_5 }=2.00molP*\frac{2molP_2Cl_5}{4molP} *\frac{239.2125gP_2Cl_5 }{1molP_2Cl_5} \\\\m_{P_2Cl_5 }=239.2125gP_2Cl_5[/tex]
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