Answer:
2
Step-by-step explanation:
[tex]\frac{7+sin^{2}\theta+cos^{2}\theta}{4sin^{2}\theta+4cos^{2}\theta}} = \frac{7+(sin^{2}\theta+cos^{2}\theta)}{4(sin^{2}\theta+cos^{2}\theta)}} =\frac{7+(1)}{4(1)}}=\frac{8}{4} =2[/tex]
[tex](sin^{2}\theta +cos^{2}\theta=1)\\[/tex]
