Respuesta :
Answer:
The Coordinates of Point C are C(5,2)
The slope of CD is 3
The possible coordinates of point D(a,b) are (6, 5) and (4, -1)
Step-by-step explanation:
According to the Question,
- Given, The end points of AB are A(2,3) and B(8,1). The perpendicular Bisector of AB is CD, and point C lies on AB. The length of the CD is √10 units.
Now, Let The Coordinates of Point C are C( x , y ) .
- Thus, C( x , y ) = [tex]\frac{(8+2)}{2} , \frac{(1+3)}{2}[/tex]
The Coordinates of Point C are C( x , y ) = [tex]\frac{(10)}{2} , \frac{(4)}{2}[/tex] ⇒C(5, 2).
- And, The slope of AB = [tex]\frac{(1-3)}{(8-2)}[/tex] ⇒ [tex]\frac{-2}{6}[/tex] ⇔ [tex]\frac{-1}{3}[/tex] .
Thus, The slope of CD is [tex]\frac{-1}{The slope of AB}[/tex] = [tex]\frac{-1}{\frac{-1}{3} }[/tex] ⇔ 3.
- Let the coordinate of D be (a, b) then
⇒ √{ (b - 2)² +(a - 5)² } = √10
on squaring both sides we get,
⇒ a² - 10a + 25 + b² - 4b + 4 = 10
⇒ a² + b² - 10a - 4b = - 19 ⇔⇔ (Equation 1)
- We Know, the slope of CD = 3
⇒Thus, (b - 2)/(a - 5) = 3
⇒ b - 2 = 3a - 15
⇒ b = 3a - 13 ⇔⇔ (Equation 2)
- Putting value of Equation 2 into Equation 1, We get
⇒a² + (3a - 13)² - 10a - 4(3a - 13) = - 19
⇒a² + 9a² - 78a + 169 - 10a - 12a + 52 = - 19
⇒10a² - 100a + 240 = 0
⇒a² - 10a + 24 = 0
⇒(a - 4)(a - 6) = 0
⇒a = 4 or a = 6
Now,
- When a = 4 , b = 3(4) - 13 ⇒ 12 - 13 ⇒ b = -1
- When a = 6, b = 3(6) - 13 ⇒ 18 - 13 ⇒ b = 5
Therefore, the possible coordinates of point D(a,b) are (6, 5) and (4, -1).
