leslierodriguezrodri leslierodriguezrodri
  • 25-06-2021
  • Mathematics
contestada

HELP ME PLEASE!!!
GIVEN sin0= √23/12
tan0= √23/11
Find cos0

HELP ME PLEASE GIVEN sin0 2312 tan0 2311 Find cos0 class=

Respuesta :

sreedevi102
sreedevi102 sreedevi102
  • 25-06-2021

Answer:

[tex]cos \theta = \frac{11}{12}[/tex]

Step-by-step explanation:

[tex]sin \theta = \frac{\sqrt{23}}{12} \ , \ tan \theta = \frac{\sqrt{23}}{11}\\\\tan \theta = \frac{sin \theta }{cos \theta }\\\\ \frac{\sqrt{23}}{11} = \frac{\frac{\sqrt{23}}{12} }{cos \theta}\\\\cos \theta = \frac{\frac{\sqrt{23}}{12} }{\frac{\sqrt{23}}{11} }\\\\cos \theta = \frac{\sqrt{23}}{12 } \times \frac{11}{\sqrt{23}}\\\\cos \theta = \frac{11}{12}[/tex]

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