notsubzeros9273 notsubzeros9273
  • 21-07-2021
  • Mathematics
contestada

Solve for x, where x > 0 and 84x(x + 2) = 90-13x. Express your answer as a simplified common fraction.

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Аноним Аноним
  • 21-07-2021

84x(x+2) = 84x² + 168x

84x² + 168x = 90 - 13x

84x² +181x - 90 = 0

bhaskara formula

[tex]\frac{-181+-\sqrt{181^{2}- 4.84.(-90) } }{168 } }[/tex]

[tex]\frac{-181+-\sqrt{32.761 +30.240} }{168}[/tex]

[tex]\frac{-181+-251}{168}[/tex]

since its a positive number, we can't use the minus

so, [tex]\frac{70}{168}[/tex]

they're both dividable by 14, so

x = [tex]\frac{5}{12}[/tex] is your answer

hope it helps :)

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