Step-by-step explanation:
[tex] \frac{x + 1}{5} + \frac{x + 1}{6} +\frac{x + 1}{7} +\frac{x + 1}{8} +\frac{x + 1}{9} +\frac{x + 1}{10 } = 0[/tex]
[tex](x + 1)( \frac{1}{5} + ... + \frac{1}{10} ) = 0[/tex]
Since the second factor is non-zero, the only possible condition for the equation to hold is,
[tex]x + 1 = 0[/tex]
[tex]x = - 1[/tex]
