wondrlndrules wondrlndrules
  • 21-09-2021
  • Mathematics
contestada

i need help with this, no idea what i'm doing

i need help with this no idea what im doing class=

Respuesta :

Hi1315
Hi1315 Hi1315
  • 21-09-2021

Answer:

[tex]- 5 {p}^{2} {q}^{2} [/tex]

Step-by-step explanation:

[tex] \frac{ {p}^{4}q }{ - 3 {p}^{3} } \times 15pq \\ \frac{ {p}^{4} q \times 15pq}{ - 3 {p}^{3} } \\ \frac{15 {p}^{(4 + 1)} {q}^{(1 + 1)} }{ - 3 {p}^{3} } \\ \frac{15 {p}^{5} {q}^{2} }{ - 3 {p}^{3} } \\ 15 {p}^{5} {q}^{2} \div - 3 {p}^{3} \\ (15 \div - 3)( {p}^{5 - 3} ) {q}^{2} \\ - 5 {p}^{2} {q}^{2} [/tex]

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