bellalongley
bellalongley bellalongley
  • 24-09-2021
  • Mathematics
contestada

How many
solutions for x does the following equation have?
4/5(20x + 5) = 16x - 2


A. 1
B. -2
C. 0
D. infinite

How many solutions for x does the following equation have 4520x 5 16x 2 A 1 B 2 C 0 D infinite class=

Respuesta :

zmcever
zmcever zmcever
  • 24-09-2021

Answer:

There are no solutions

Step-by-step explanation:

4/5 ( 20x + 5 ) = 16x - 2

Distibute on the left:

( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 2

16x + 4 = 16x - 2

Subtract 16x from both sides:

4=-2

Add 2 to each side:

6=0

No solutions

Answer Link
ivy12345
ivy12345 ivy12345
  • 24-09-2021
the answer will be c zero
Answer Link

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