[tex] \sf{ \red{ \underline{Solution - }}} \\ [/tex]
Given equation is 1/(x+2) - 1/(x-2) = 1
=> [(x-2)-(x+2)]/(x+2)(x-2) = 1
=> (x-2-x-2)/(x²-4) = 1
=> (-2-2)/(x²-4) = 1
=> -4/(x²-4) = 1
=> x²-4 = -4
=> x²-4+4 = 0
=> x² +0 = 0
=> x² = 0
The standard form is x² = 0 or x²+0x+0 = 0
Here I have used this formulae in your all questions.
The standard quadratic equation is ax²+bx+c = 0
Hope this helps!!
