nadiamahmud7586
nadiamahmud7586 nadiamahmud7586
  • 22-11-2021
  • Physics
contestada

A rocket accelerates from rest at 27 m/s^2 for 11 s.
How far will it cover during this time?
Answer in units of m.

Respuesta :

Аноним Аноним
  • 22-11-2021

Answer:

297m

Explanation:

297 x 11

:)

Answer Link
aidanlsachs
aidanlsachs aidanlsachs
  • 22-11-2021
Use the equation v^2 = v0^2 + 2ax where v is the final velocity, v0 is the initial velocity, a is the acceleration, and x is the displacement.

We also must find v using the equation v = v0 + at.

v = 0 + 27(11)
=> v = 297 m/s

Then using the first equation,

297^2 = 0^2 + 2(27)x
=> 88209 = 54x
=> x = 1633.5m
Answer Link

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