grantwenciker grantwenciker
  • 23-01-2022
  • Mathematics
contestada

For what value of x is sin(x) = cos(32°), where 0°< x < 90°?
A.
64°
B.
58°
C.
32°
D.
13°

Respuesta :

algebraic12 algebraic12
  • 23-01-2022

Answer:

B

Step-by-step explanation:

Use the cofunction identies that states that

[tex] \sin(90 - x) = \cos(x) [/tex]

[tex] \sin((90 - x)) = \cos(32) [/tex]

[tex] \sin(90 - 32) = \cos(32) [/tex]

[tex] \sin(58) = \cos(32) [/tex]

B is the answer.

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