Answer:
The minimum number of bits necessary to address 8K words is 13.
Explanation:
You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.
8000 words can be addressed with 2 units. Now you have to find the value of n that approximates to the number of words.
2² = 4
24
16
27 = 128
210 1024
212 = 4096
213
8192
So you can see that 13 bits are needed to address 8K words.
