jakemarsh082 jakemarsh082

25-02-2022
Physics

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When the potential difference between the plates of a capacitor is increased by 3.50 V , the magnitude of the charge on each plate increases by 15.0 μC . What is the capacitance of this capacitor in μF?

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zsm2800 zsm2800

25-02-2022

Answer:

42.9 μF

Explanation:

V = 3.50 V, Q = 150 μC

C = Q/V = 150/3.50 μF = 42.9 μF

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