Answer:
[tex]x=\dfrac{17}{4}[/tex]
.
Step-by-step explanation:
It is given that ABCD is an isosceles trapezoid and it has diagonals AC = 10x + 7 and BD = 2x + 41.
We need to find the value of x.
We know that the diagonals of an isosceles trapezoid are equal.
[tex]AC=BD[/tex]
[tex]10x+7=2x+41[/tex]
[tex]10x-2x=41-7[/tex]
[tex]8x=34[/tex]
[tex]x=\dfrac{34}{8}[/tex]
[tex]x=\dfrac{17}{4}[/tex]
Hence the value of x is [tex]\dfrac{17}{4}[/tex].
