I would recommend getting x alone in the second equation so that you can substitute whatever x equals to in the first equation. This is what I'll be doing for my first step: x=-5y-19
Then, substitution: 3(-5y-19)+5y=-7 -15y-57+5y=-7
Add 57 to both sides: -15y+5y=50
Add like things (the y's): -10y=50
Divide both sides by -10 to get y: y=-5
Substitute -5 into x=-5y-19: x=-5(-5)-19 x=25-19 x=6
