jessejames0223 jessejames0223

24-04-2022
Mathematics

contestada

Assume z is a standard normal random variable. What is the value of z if the area between –z and z is 0.7580?

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Аноним Аноним

24-04-2022

to the right is P(z> Z)

so P(z>Z) = 0.9909

P(z< Z) = 1- 0.9909 = 0.0091

Closest values from a z-table

P(z< -2.37) = 0.00889 (-0.00011 away)

p(z< -2.36) = 0.00914 (+0.00014 away)

so the answer must be (c) since it is between -2.36 and -2.37

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