winfreyduke14 winfreyduke14

24-05-2022
Mathematics

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Suppose that y varies inversely with the square of x and y = 50 when x = 4. Find y when x = 5

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Аноним Аноним

24-05-2022

Answer:

y = 32.

Step-by-step explanation:

y = k/x^2 where k is the constant of variation

When y = 50 x = 4, so

50 = k / (4)^2

f = 50 * 4^2 = 800.

So the relation is

y = 800/x^2

When x = 5

y = 800/5^2

= 32.

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