7004035 7004035
  • 26-05-2022
  • Mathematics
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How many solutions exist for each system of equations?
x + 2y = –1
2x + 3y = 0

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Аноним Аноним
  • 26-05-2022

Answer:

2 solutions   x = 3 y = -2.

Step-by-step explanation:

x + 2y = –1

2x + 3y = 0

Multiply first equation by -2:

-2x - 4y = 2      Adding this to second equation:

       - y = 2

y = -2.

Plug this into first equation:

x - 4 = -1

x = 3.

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