Respuesta :
21.3 KJ/mol is the ( ΔH°vap ) of a liquid.
The Clausius - Clapeyron equation -
- The Clausius - Clapeyron equation relates the heat of vaporization and vapor pressure.
- The Clausius Clapeyron equation is shown below in a form similar to a linear equation (y=mx+b).
- Vapor pressure rises non-linearly as temperature rises since the y-term in this case is a natural log of the vapor pressure
T1 = 85.2 oC
=(85.2 + 273)K
= 358.2 K
T2 = 95.6 oC
=(95.6 + 273)K
= 368.6 K
P1 = 6.21 * 10^2 torr
P2 = 7.6 * 10^2 torr
use
ln(P2/P1) = (ΔH/R) * (1/T1 - 1/T2)
ln(7.6 * 10^2/6.21 * 10^2) = ( ΔH/8.314) * (1/358.2 - 1/368.6)
0.202 = (ΔH/8.314) * (7.877 * 10^-5)
ΔH = 21320 J/mol
= 21.3 KJ/mol
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