According to the question:
n = 1
K = 5 × [tex]10^{4}[/tex]
T = 298 K
Gibb's energy, ΔG° = - RT ln K
= -8.314 × 298 × ln 5 × [tex]10^{4}[/tex]
= - 9.69 × [tex]10^{3}[/tex] J/mol
E°cell = [tex]\frac{RT lnK}{nF}[/tex]
= [tex]\frac{8.314*298 ln 5*10^{4} }{2*96500}[/tex]
= 5 × [tex]10^{-2}[/tex]
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