We have the next function
[tex]h(x)=\frac{3}{4}x+12[/tex]
First we need to make h(x)=y
[tex]y=\frac{3}{4}x+12[/tex]
Then we make x=y and y=x
[tex]x=\frac{3}{4}y+12[/tex]
Then we isolate the y
[tex]x-12=\frac{3}{4}y[/tex][tex]4(x-12)=3y[/tex][tex]y=\frac{4(x-12)}{3}[/tex][tex]y=\frac{4x-48}{3}[/tex]
Therefore the inverse function is
[tex]h^{-1}(x)=\frac{4x-48}{3}[/tex]
