LawaiaL466529 LawaiaL466529
  • 25-10-2022
  • Mathematics
contestada

juans dog Stan's two feet and 3 inches tall Peters dog stands 9 in tall how much taller is juans dog than Peters dog

Respuesta :

MychaelH558643 MychaelH558643
  • 25-10-2022

To answer this question, we need to transform all the values into one type of measure. In this case, we can work with inches. Then, we have:

[tex]2ft\cdot\frac{12in}{1ft}=24in[/tex]

Then, we have that in two feet we have 24 inches. Then, we have:

Juan's dog: 24 inches + 3 inches ---> 27 inches tall.

Peter's dog: 9 inches tall.

Now, how much taller is Juan's dog than Peter's dog is:

[tex]\frac{\text{Juan's dog}}{\text{Peter's dog}}=\frac{27in}{9in}=3[/tex]

Therefore, Juan's dog is 3 times taller than Peter's dog.

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