Given:
[tex]36y^3-49y=0[/tex]solve for y:
[tex]\begin{gathered} 36y^3-49y=0 \\ y(36y^2-49)=0 \\ y=0;36y^2-49=0 \end{gathered}[/tex]Value of y is zero and
[tex]\begin{gathered} 36y^2-49=0 \\ 36y^2=49 \\ y^2=\frac{49}{36} \\ y=\pm\sqrt[]{\frac{49}{36}} \\ y=\pm\sqrt[]{1.361111} \\ y=\pm1.166 \\ y=1.166,y=-1.166 \end{gathered}[/tex]