FrazierZ270243 FrazierZ270243

25-10-2022
Mathematics

contestada

Find the 11th term of the sequence: 32805, 10935, 3645...

Respuesta :

JaydalynC350742 JaydalynC350742

25-10-2022

first term a=32805

common ration: r=10935/32805=1/3

11th term:

[tex]\begin{gathered} a_{11}=32805(\frac{1}{3})^{11-1} \\ a_{11}=32805(\frac{1}{3})^{10} \\ a_{11}=32805(\frac{1}{59049}) \\ a_{11}=0.555 \end{gathered}[/tex]

So the 11th term is 0.555

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