Given:
Expression is
[tex]f(x)=(x-3)^2(x-1)[/tex]
Required:
Find zeros of polynomial and multiplicity of zeros.
Explanation:
We will find zeros of polynomial by equating f(x) = 0.
That is,
[tex]\begin{gathered} (x-3)^2(x-1)=0 \\ x=3,3,3,1 \end{gathered}[/tex]
Answer:
Hence, zeros of function is 3, 1 and multiplicity of 3 equal 3 and 1 equal 1.
