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  • 22-04-2017
  • Mathematics
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k^{2} -9 \k^{2} -7k+12

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PsychrolutesMarcidus
PsychrolutesMarcidus PsychrolutesMarcidus
  • 22-04-2017
[tex] \frac{k^2-9}{k^2-7k+12} [/tex]        Factor
= [tex]\frac{(k+3)(k-3)}{(k-3)(k-4) }[/tex] Eliminate (k-3)
=[tex]}\frac{(k-3)}{(k-4) }[/tex]                 Isolate k

k-3=0
k=3

k-4=0
k=4

k is equal to 3,4
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