1. Angle PAB is 90 degrees, as it is formed from the tanget to the circle at A, and the radius drawn to A.
2. AB=BC, because tangents drawn to a circle from the same point are equal.
3. PB is Common, so by the side-side-side congruence postulate, triangles ABP and CBP are congruent.
4. So measure of m(BPA)=x/2 and m(ABP)=73/2.
5. [tex] \frac{x}{2}+90+ \frac{73}{2}=180 [/tex]
[tex] \frac{x+73}{2}=90 [/tex]
[tex]x+73=180[/tex], x= 107 degrees.
