Respuesta :

apologiabiology
v=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2

so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)

it is 4 times the old one

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