ArtG
ArtG
23-06-2017
Mathematics
contestada
find the vertex of the parabola y=-2x^2-8x-15
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Banabanana
Banabanana
23-06-2017
[tex]y=-2x^2-8x-15 \\ a=-2; \ b=-8; \ c=-15 \\ \\ x= \frac{-b}{2a}= \frac{-(-8)}{2*(-2)} = \frac{8}{-4} =-2 \\ \\ y=-2x^2-8x-15 =-2(-2)^2-8(-2)-15 =-8+16-15=-7[/tex]
Answer: (-2, -7)
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playerawesome1
playerawesome1
23-06-2017
y = -2x^2 - 8x - 15 x = -b/2a
-(-8)/2(-2)
8/-4 = -2
y = -2(-2)^2 - 8(-2) - 15
y = -2(4) + (16) - 15
-8 + 16 -15
8 - 15 = -7
vertex: ( -2, -7)
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