write in y=ax²+bx+c form
solve for y
given
[tex]\frac{x+5}{3}=-2y+4[/tex]
solve for y
easy
minus 4 both sides
[tex]\frac{x+5}{3}-4=-2y[/tex]
times -1/2 to both sides
[tex]\frac{x+5}{-6}+2=y[/tex]
[tex]y=\frac{x+5}{-6}+2[/tex]
[tex]y=\frac{-x}{6}-\frac{6}{5}+2[/tex]
2=10/5
[tex]y=\frac{-1}{6}x-\frac{6}{5}+\frac{10}{5}[/tex]
[tex]y=\frac{-1}{6}x+\frac{4}{5}[/tex]
y=ax²+bx+c
[tex]y=0x^2+\frac{-1}{6}x+\frac{4}{5}[/tex]
a=0
b=[tex]\frac{-1}{6}[/tex]
c=[tex]\frac{4}{5}[/tex]
