Respuesta :

Julik
[tex]\left \{ {{4x+6y=8} \atop {5x-4y=25}} \right. \\ \left \{ {{4x+6y=8} \atop {5x=25+4y}} \right.\\ \left \{ {{4x+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{4(5+0.8y)+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{20+3.2y+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{9.2y=-12} \atop {x=5+0.8y }} \right. \\ \left \{ {{y= -\frac{12}{9.2} } \atop {x=5+0.8y }} \right. \\ \left \{ {{y= -\frac{120}{92} } \atop {x=5+0.8(-\frac{12}{9.2}) }} \right. \\ [/tex]
[tex] \left \{ {{y= -1\frac{28}{92} } \atop {x=5-\frac{96}{92} }} \right. \\ \left \{ {{y= -1\frac{7}{23} } \atop {x=5-1\frac{1}{23} }} \right. \\ \left \{ {{y= -1\frac{7}{23} } \atop {x=4\frac{1}{23} }} \right. \\ [/tex]
[tex]\boxed{(x; y)=(4\frac{1}{23}; -1\frac{7}{23}) }[/tex]





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