jahnays16
jahnays16 jahnays16
  • 21-09-2017
  • Mathematics
contestada

.help me thanks much

help me thanks much class=

Respuesta :

choixongdong
choixongdong choixongdong
  • 21-09-2017
(16x^1/6y^-2)^3/2 / (x^-1/6y^6)^3/2

=(4^2)^3/2 (x^1/6)^3/2 (y^-2)^3/2 / (x^-1/6)^3/2(y^6)^3/2
= 4^3   x^1/4 y^-3  / x^-1/4 y ^9
= 64 x^(1/4 +1/4) y^(-3-9)
= 64 x^1/2 y^-12
= 64 x^1/2 / y^12

answer is D.64 x^1/2 / y^12
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