[tex]\frac{7}{8}+\frac{3}{4}\\\\find\ LCD\\\\8=4\times2\\\\therefore\ LCD(\frac{7}{8};\ \frac{3}{4})=8\\\\\frac{3}{4}=\frac{3\times2}{4\times2}=\frac{6}{8}\\\\solution:\\\\\frac{7}{8}+\frac{3}{4}=\frac{7}{8}+\frac{6}{8}=\frac{7+6}{8}=\frac{13}{8}=\frac{8+5}{8}=\frac{8}{8}+\frac{5}{8}=1+\frac{5}{8}=\huge\boxed{1\frac{5}{8}} [/tex]
