sulaimanshabs14
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  • 23-04-2018
  • Mathematics
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Rationalize
[tex] \frac{1}{2 \sqrt{7} + 3 \sqrt{3} } [/tex]

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Аноним Аноним
  • 23-04-2018
[tex] \dfrac{1}{2 \sqrt{7} + 3 \sqrt{3} } [/tex]

[tex]= \dfrac{1}{2 \sqrt{7} + 3 \sqrt{3} } \times \dfrac{2 \sqrt{7} - 3 \sqrt{3}}{2 \sqrt{7} - 3 \sqrt{3}} [/tex]

[tex] =\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{(2\sqrt{7})^2 - (3\sqrt{3})^2} [/tex]

[tex] =\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{28 - 27} [/tex]

[tex] =\dfrac{2 \sqrt{7} - 3 \sqrt{3}}{1} [/tex]

[tex]=2 \sqrt{7} - 3 \sqrt{3}[/tex]

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