We have the following functions: f (x) = 3x ^ 2-1 g (x) = x + 2 Adding both functions we have: (f + g) (x) = f (x) + g (x) (f + g) (x) = (3x ^ 2-1) + (x + 2) (f + g) (x) = 3x ^ 2 + x + 1 Answer: The answer for this case is given by: (f + g) (x) = 3x ^ 2 + x + 1 option 3
