EmceeCalla EmceeCalla
  • 24-04-2018
  • Mathematics
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rationalize the denominator: 6/√8x

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mkryukova19 mkryukova19
  • 24-04-2018
[tex] \frac{6}{ \sqrt{8x} } = \frac{6* \sqrt{8x} }{ ( \sqrt{8x} )(\sqrt{8x} ) } = \frac{6 \sqrt{8x} }{8 x^{2} } = \frac{3 \sqrt{8x} }{4 x^{2} } [/tex]
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