Answer:
0.092 is the required proportion.
Step-by-step explanation:
We are given the following in the question:
A normal distribution.
We have to find the proportion of data lying between z = 1.00 and z = 1.50.
P(between z = 1.00 and z = 1.50)
[tex]P(.001 \leq z \leq 1.50)\\= P(z \leq 1.50) - P(z < 1.00)\\= 0.933 - 0.841 = 0.092 = 9.2\%[/tex]
Thus, 0.092 is the proportion of data located between z = 1.00 and z = 1.50.
